string写时复制:将字符串str1赋值给str2后,除非str1的内容已经被改变,否则str2和str1共享内存。当str1被修改之后,stl才为str2开辟内存空间,并初始化。
#include <cstring>
#include <string>
#include <cstdio>
#include <iostream>
using namespace std;
void fun1()
{
string s1 = "hello, world!";
string s2 = s1;
cout << "before: " << s2 << endl;
char* ptr = const_cast<char*>(s1.c_str());
*ptr = 'f';
cout << "after: " << s2 << endl;
}
void fun2()
{
string s1 = "hello, world!";
string s2 = s1;
cout << "before: " << s2 << endl;
s1[0] = 'f';
cout << "after: " << s2 << endl;
}
int main()
{
cout << "fun1: " << endl;
fun1();
cout << "fun2: " << endl;
fun2();
return 0;
}
注意:fun1中,通过char*修改s1行为,并不会触发stl的复制操作,因为stl并不认为通过char* 对s1的修改是对string s1的修改。
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